- From: Xavier Franc <xfranc@online.fr>
- Date: Wed, 04 Feb 2004 17:07:04 +0100
- To: public-qt-comments@w3.org
If I have well understood the problem,
a solution in XPath2 could be:
P[ @leukemia='no'
and (every $a in ancestor::P satisfies $a/@leukemia='yes') ]
hope this helps
>Maarten,
>
>Thankyou for sending this comment:
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>http://lists.w3.org/Archives/Public/public-qt-comments/2003Nov/0302.html
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Received on Wednesday, 4 February 2004 11:09:19 UTC