- From: Xavier Franc <xfranc@online.fr>
- Date: Wed, 04 Feb 2004 17:07:04 +0100
- To: public-qt-comments@w3.org
If I have well understood the problem, a solution in XPath2 could be: P[ @leukemia='no' and (every $a in ancestor::P satisfies $a/@leukemia='yes') ] hope this helps >Maarten, > >Thankyou for sending this comment: > >http://lists.w3.org/Archives/Public/public-qt-comments/2003Nov/0302.html > > >
Received on Wednesday, 4 February 2004 11:09:19 UTC