> It is a function! It returns a permutation of its input. It seems my misunderstanding comes from the expectation that a function is always well-defined, or at least determinate in a way that if a = b then f(a) = f(b) Obviously that's not the case for fn:unordered > It's only difference from other functions is in its motivation: it exists in > order to be optimized. I'm not sure if I'm the only one with this problem of understanding. An explanatory note would be of great benefit. Thanks for the enlightenment, Oliver /-------------------------------------------------------------------\ | ob|do Dipl.Inf. Oliver Becker | | --+-- E-Mail: obecker@informatik.hu-berlin.de | | op|qo WWW: http://www.informatik.hu-berlin.de/~obecker | \-------------------------------------------------------------------/Received on Thursday, 25 September 2003 08:25:40 UTC
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