RE: ORA-FO-UNORDERED 15.1.15 fn:unordered

> It is a function! It returns a permutation of its input.

It seems my misunderstanding comes from the expectation that a function
is always well-defined, or at least determinate in a way that if a = b 
then f(a) = f(b)
Obviously that's not the case for fn:unordered

> It's only difference from other functions is in its motivation: it exists in
> order to be optimized.

I'm not sure if I'm the only one with this problem of understanding.
An explanatory note would be of great benefit.

Thanks for the enlightenment,
Oliver


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|  ob|do        Dipl.Inf. Oliver Becker                             |
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Received on Thursday, 25 September 2003 08:25:40 UTC