- From: Jeni Tennison <jeni@jenitennison.com>
- Date: Mon, 18 Aug 2003 22:25:08 +0100
- To: Tobias Reif <tobiasreif@pinkjuice.com>
- CC: public-qt-comments@w3.org
Hi Tobi,
> I need to get a sequence of the characters in a string.
>
> The current draft
> http://www.w3.org/TR/xquery-operators/#func-tokenize
> says
> 'fn:tokenize("abba", ".?") returns ("a", "b", "b", "a")'
>
> I don't understand why it should.
The definition of the fn:tokenize() function says:
"If the supplied $pattern matches a zero-length string, the
fn:tokenize() function breaks the string into its component
characters. The nth character in the $input string becomes the nth
string in the result sequence; each string in the result sequence
has a string length of one."
In the example above, the pattern ".?" is a pattern that matches a
zero-length string; therefore, the fn:tokenize() function breaks the
string into its component characters. You would get the same behaviour
from any pattern that matches a zero-length string, such as "" or
".*".
Does that explain the example sufficiently?
Cheers,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
Received on Monday, 18 August 2003 17:25:07 UTC