- From: Oriol Brufau via GitHub <sysbot+gh@w3.org>
- Date: Fri, 06 Nov 2020 00:59:21 +0000
- To: public-css-archive@w3.org
Regarding complexity, we have (from hardest to easiest):
1. `:has()`
2. `:has-child(S) = :has(> :is(S))` (#4903)
3. `:nth-children(An+B of S) = :has-child(:nth-child(An+B of S):nth-last-child(1 of S))`
(or maybe `= :is(:has-child(:nth-child(An+B of S):nth-last-child(1 of S)), :not(:has-child(S)))` if `B=0` or `A,B≠0, A∣B, A*B<0`)
So this one seems the most feasible, and `:has()` might be unfeasible (for the web, for now). But if `:has-child()` is feasible, I would prefer it over this one.
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Received on Friday, 6 November 2020 00:59:23 UTC