- From: Chris Wilson <cwilso@google.com>
- Date: Tue, 11 Jun 2013 16:58:58 -0700
- To: Ehsan Akhgari <ehsan.akhgari@gmail.com>
- Cc: "public-audio@w3.org" <public-audio@w3.org>
- Message-ID: <CAJK2wqUcWD8aOJg5wvLrjaaqr+6sg0PbGvkmDofy3+865qxySA@mail.gmail.com>
On Tue, Jun 11, 2013 at 4:44 PM, Ehsan Akhgari <ehsan.akhgari@gmail.com>wrote: > On Tue, Jun 11, 2013 at 7:30 PM, Chris Wilson <cwilso@google.com> wrote: > >> Why would passing through the input make more sense to you? >> > > Because that's what many of the other processing nodes (such as GainNode, > DelayNode, etc) do by default, so it seems more consistent. > Not exactly. GainNode and DelayNode simply initialize their parameters to a given value that happens to result in a pass-through. Gain obviously is set to unity as a default; delay has zero as the initial delayTime. Convolver isn't initialized to a buffer that results in pass-through - it's essentially still in an uninitialized state. [Constructor(AudioBuffer buffer)] >> > interface ConvolverNode : AudioNode { > boolean normalize; > }; > > And that would eliminate the question of what to do with a null > AudioBuffer altogether. > True, although it's handy to be able to change the buffer later. > If I was using the convolver as an effects node in a mixer, passing >> through the input until I set the buffer would "double up" the original >> signal if the effects mix were set to 50%. That seems like odd behavior. >> > > I'm not quite sure what that means... Can you please clarify? > If I'm using Convolver to get reverb on an effect send, I'd kind of expect no original signal bleed-through until I initialize it. > Also, does this behavior for other node types surprise you in the same > way? Really what's more interesting to me is consitency, one way or > another. > I see what you're saying, but from using the nodes, I don't think it's actually consistency in the way you'd expect. BiquadFilter and DynamicsCompressor don't work this way, for example; however, I note that Waveshaper does (explicitly just pass through), and it's the only other "through" node with a buffer, so perhaps that is the best approach. Since Chris already agreed, go for it. I think it's slightly odd from the usage side, but not that big a deal.
Received on Tuesday, 11 June 2013 23:59:29 UTC