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Re: [css3-images] linear-gradient keywords and angles are opposite

From: Philippe Wittenbergh <ph.wittenbergh@l-c-n.com>
Date: Thu, 9 Jun 2011 10:46:48 +0900
Cc: Brian Manthos <brianman@microsoft.com>, Brad Kemper <brad.kemper@gmail.com>, "www-style@w3.org list" <www-style@w3.org>, "Tab Atkins Jr." <jackalmage@gmail.com>
Message-Id: <DC0EDC2B-FD00-48AF-A8C6-1082435124F2@l-c-n.com>
To: Sylvain Galineau <sylvaing@microsoft.com>

On Jun 9, 2011, at 9:44 AM, Sylvain Galineau wrote:

> It's important to note here that we are not just talking about static gradient
> backgrounds but the animation of their value. It turns out there are number of 
> issues in those scenarios, of which this is one.

Ok, I found back the issue with animation you are referring to

> A safe - I think - working assumption is that CSS authors are very familiar
> with top/right/bottom/left and the spatial relationship between them. The 
> question is whether the following would be natural to web authors: that 
> transitioning a linear gradient from 0deg to 90deg is equivalent on the keyword 
> side to going from bottom to left. 
(earlier in this thread)

That is assuming that 0deg points up and 90deg points right-wards. Most designers I know are more familiar with the Photoshop gradients (0deg is right-wards). That point has been made by Brad, vocally. And I support him in this.

I mean, I don't really see what the issue with animation or transition is.

Philippe Wittenbergh
Received on Thursday, 9 June 2011 01:47:15 UTC

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