On Thu, 12 Mar 2009 17:29:46 +0100 Christian de Sainte Marie <csma@ilog.fr> wrote: > Michael Kifer wrote: > > [...] This is what I was > > planning to use for aggregates (I proposed this several months ago in an email) > > and for shorthands like a[b->c b->d] == a[b-> {c d}] > > > Does == mean equivalent? yes > If we do something like this, how do we deal with set-valued attributes? > > I mean: is a[b->{c d} b->{e f}] equivalent to a[b->{c d e f}] yes > or a[b->{{c d}{e f}}] or a[b->{c d {e f}}] etc? No. The above is invalid syntax. The domain does not contain sets - only elements. So, the value of an attribute is a set, not a set of sets. michael > > (Btw, this is another form of the question I had in mind with what you called my "puzzle" about a[b->a.b], in [1]). > > Cheers, > > Christian > > [1] http://lists.w3.org/Archives/Public/public-rif-wg/2009Mar/0009.html > >Received on Thursday, 12 March 2009 17:59:05 GMT
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