Michael Kifer wrote: > [...] This is what I was > planning to use for aggregates (I proposed this several months ago in an email) > and for shorthands like a[b->c b->d] == a[b-> {c d}] Does == mean equivalent? If we do something like this, how do we deal with set-valued attributes? I mean: is a[b->{c d} b->{e f}] equivalent to a[b->{c d e f}] or a[b->{{c d}{e f}}] or a[b->{c d {e f}}] etc? (Btw, this is another form of the question I had in mind with what you called my "puzzle" about a[b->a.b], in [1]). Cheers, Christian [1] http://lists.w3.org/Archives/Public/public-rif-wg/2009Mar/0009.htmlReceived on Thursday, 12 March 2009 16:30:47 GMT
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