- From: Dr. Yves Forkl <Y.Forkl@srz.de>
- Date: Fri, 24 Feb 2012 19:27:01 +0100
- To: XProc Dev <xproc-dev@w3.org>
Please forgive if this is a trivial question, but I couldn't find an example of how to do this anywhere.
Very much like with XSLT, I would like to reference the value of a parameter that has been passed to the processor from the command line.
The command line part, of course, is easy with Calabash: --with-param myparam=myvalue
As far as I have understood, XProc has no global variables, but can pass parameters through its steps. However, I can't figure out how to access the parameter within an XPath expression when setting variable myvar in a step of my pipeline:
<p:declare-step name="main" type="srz:pipeline1"
xmlns:p="http://www.w3.org/ns/xproc"
xmlns:srz="http://xmlns.srz.de/yforkl/xproc"
version="1.0">
<p:input port="source"/>
<p:output port="result" sequence="true"/>
<p:input port="parameters" kind="parameter"/>
...
<p:declare-step name="step3" type="srz:step3">
<p:input port="source"/>
<p:output port="result" sequence="true">
<p:pipe step="store-each" port="result"/>
</p:output>
<p:input port="parameters" kind="parameter"/>
...
<p:variable name="myvar" select="$myparam"/>
...
</p:declare-step>
....
<srz:step3/>
</p:declare-step>
Do I need to read out <c:param-set> and parse its <c:param> children? Or what else am I missing?
Yves
Received on Sunday, 26 February 2012 22:20:02 UTC