- From: <Toman_Vojtech@emc.com>
- Date: Wed, 21 Apr 2010 03:26:43 -0400
- To: <xproc-dev@w3.org>
- Message-ID: <997C307BEB90984EBE935699389EC41C01348D18@CORPUSMX70C.corp.emc.com>
Christopher, Try the following: <cx:unzip> ... <p:with-option name="content-type" select="'text/plain'"/> ... </cx:unzip> (Single quotes around the text/plain value so that it is treated as a string and not as an XPath expression) That might help. Vojtech From: xproc-dev-request@w3.org [mailto:xproc-dev-request@w3.org] On Behalf Of Christopher Ball Sent: Wednesday, April 21, 2010 3:20 AM To: xproc-dev@w3.org Subject: Missing something basic . . ? Hello, I am trying to process some zipped text files in xproc (leveraging a Calabash extension), but I am getting tripped up by base64 encoding. My first draft of the xproc is below. Unfortunately, the content-type option on cx:unzip seems to be getting ignored and I end up with an output file of the following nature: <!-- Output Snippet --> <c:data xmlns:c="http://www.w3.org/ns/xproc-step" name="InputFile1.txt" content-type="">LS0tLS1CRUdJTiBQUklWQUNZLUVOSEFOQ0VEIE1FU1NBR0UtLS0tLQ0K UHJvYy1UeXBlOiAyMDAx . . . </c:data> I am I missing the obvious . . . or trying to do the impossible? Most grateful for any feedback, Christopher <!-- xProc File --> <?xml version="1.0" encoding="UTF-8"?> <p:declare-step xmlns:p="http://www.w3.org/ns/xproc" xmlns:cx="http://xmlcalabash.com/ns/extensions" xmlns:c="http://www.w3.org/ns/xproc-step" xmlns:html="http://www.w3.org/1999/xhtml" name="aMeaninglessName" version="1.0" > <p:input port="source"> <p:empty/> </p:input> <p:declare-step type="cx:unzip" version="1.0"> <p:output port="result"/> <p:option name="href" required="true"/> <p:option name="file"/> <p:option name="content-type"/> </p:declare-step> <p:variable name="startingFileNumber" select="'1'"/> <p:variable name="endingFileNumber" select="'1'"/> <p:variable name="source-folder" select="'../zippedFiles/'"/> <p:directory-list> <p:with-option name="path" select="$source-folder"> <p:empty/> </p:with-option> </p:directory-list> <p:for-each name="ZipedHTMLFile"> <p:iteration-source select="//c:file[position() ge number($startingFileNumber) and position() le number($endingFileNumber)]"/> <p:variable name="filename" select="c:file/@name"/> <!-- Load from Zip file --> <cx:unzip name="get-XML"> <p:with-option name="href" select="concat($source-folder,$filename)"/> <p:with-option name="file" select="replace($filename,'.zip','.txt')"/> <p:with-option name="content-type" select="text/plain"/> </cx:unzip> <p:store href="../output/processed.xml" name="store"/> </p:for-each> </p:declare-step>
Received on Wednesday, 21 April 2010 07:27:26 UTC