- From: G. Ken Holman <gkholman@CraneSoftwrights.com>
- Date: Thu, 14 Nov 2002 09:00:11 -0500
- To: <www-xsl-fo@w3.org>
At 2002-11-14 04:51 -0500, Eklund Anders wrote:
>I have an .xml-file with tables. The problem is that I don't know the
>number of columns in each table.
>Then I don't know how many <fo:table-column> I need to have a proportional
>table where all tables have the same width.
You will have to go to the effort of anticipating your column needs,
usually by practically duplicating the algorithm for creating your columns
but only in order to obtain a count.
Your example data was easy, in that each row of each table has the same
number of columns, so my answer to your question looks almost too easy
below. But, you win if that is truly the shape of your data. The problem
comes when you have an arbitrary number of columns in an arbitrary number
of rows and you want to find the largest number of columns of all the
rows. This is left as an exercise to the reader!
I hope this helps.
........................ Ken
<fo:table>
<xsl:for-each select="row[1]/column">
<fo:table-column column-width="50pt"/>
</xsl:for-each>
<fo:table-body>
<xsl:for-each select="row">
<fo:table-row>
<xsl:for-each select="column">
<fo:table-cell>
<fo:block><xsl:value-of select="."/></fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
</xsl:for-each>
</fo:table-body>
</fo:table>
--
Upcoming hands-on in-depth XSLT/XPath and/or XSL-FO:
- North America: Feb 3 - Feb 7,2003
G. Ken Holman mailto:gkholman@CraneSoftwrights.com
Crane Softwrights Ltd. http://www.CraneSoftwrights.com/f/
Box 266, Kars, Ontario CANADA K0A-2E0 +1(613)489-0999 (F:-0995)
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Next conference training: 2002-12-08,03-03,06
Received on Thursday, 14 November 2002 09:00:23 UTC