- From: Kirmse, Daniel <daniel.kirmse@sap.com>
- Date: Wed, 21 Jan 2004 12:49:20 +0100
- To: www-xpath-comments@w3.org
- Message-ID: <22772E6015DA354B84C6F8DB8BF60504D0ECD2@dewdfx13.wdf.sap.corp>
Forget about it! I finally found out how to achieve this.
 
-----Ursprüngliche Nachricht-----
Von: www-xpath-comments-request@w3.org [mailto:www-xpath-comments-request@w3.org] Im Auftrag von Kirmse, Daniel
Gesendet: Mittwoch, 21. Januar 2004 10:04
An: www-xpath-comments@w3.org
Betreff: Retrieving parts of a document
 
Hi,
is there a way to retrieve a part of a document as XML?
Suppose this document:
<?xml version="1.0"?>
<!DOCTYPE chapter PUBLIC "-//X-HIVE/Generated Public ID 101//EN" "dtd/books.dtd">
<chapter>
  <title>Data Model</title>
  <section>
    <title>Syntax For Data Model</title>
  </section>
  <section>
    <title>XML</title>
    <section>
      <title>Basic Syntax</title>
    </section>
    <section>
      <title>XML and Semistructured Data</title>
    </section>
  </section>
</chapter>
The result I have in mind is:
  <section>
    <title>XML</title>
    <section>
      <title>Basic Syntax</title>
    </section>
    <section>
      <title>XML and Semistructured Data</title>
    </section>
  </section>
 
By using a XPath expression like /chapter/section[child::title/text() = "XML"] I would merely navigate to the context of node "section" (Well maybe the phrasing is not right. I hope I made you understand my intention).
Do I have to use XQuery to accomplish that? Well I think I could write a XQuery expression for that example that generates the output. But what if I do not know the structure of the subtree/part of document to retrieve but only the structure of the root node of this subtree/part of document?
 
Thanks,
Daniel
Received on Wednesday, 21 January 2004 06:52:16 UTC