- From: <petsa@us.ibm.com>
- Date: Thu, 20 May 1999 14:46:04 -0400
- To: Marina_Nikitina@infoimage.com
- cc: Www-Xml-Schema-Comments@w3.org
- Message-ID: <85256777.00671795.00@D51MTA03.pok.ibm.com>
Marina:
Thanks for your comments. I'm glad someone is reading the draft with care!
You raise 3 points:
1. Yes, h must >= 0. We will fix this.
2. For some specific values x = v.
3. Since values in C are approximations for values in M,
many values in M map to a single value in C. Perhaps
this needs to be made more specific.
Regards, Ashok
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To: www-xml-schema-comments@w3.org
cc: (bcc: Ashok Malhotra/Watson/IBM)
Subject: exact and approximate
In 2.5.1.4 you are defining approximate datatypes as follows:
Then for every value v' in C, there is a corresponding value v in M and a real
value h such that P(x) = v' for all X in M such that |v - x| < h.
First of all, because of absolute value, h should be >0 (or >=0).
Then x in M must be different from v in M. So, you better say , for example,
... and a real value h >0 such that P(x) = v' for all x != v in M such that |v -
x| < h
Next: Furthermore, for at least one value v' in C, there is more than one value
y in M such that P(y) = v'
Question: is it possible for v'' from C and v'' !=v' that P(y) =v' and
P(y)=v''?
I am just trying to understand your concept of "approximate datatype".
Thanks
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Received on Thursday, 20 May 1999 14:46:18 UTC