- From: Cameron McCormack <cam@mcc.id.au>
- Date: Thu, 13 Feb 2014 20:55:38 +1100
- To: Paul LeBeau <paul.lebeau@gmail.com>
- CC: www-svg <www-svg@w3.org>
On 13 February 2014 8:22:48 PM AEDT, Paul LeBeau <paul.lebeau@gmail.com> wrote: >Hi Cameron > >> In the section of each command it describes what effect the current >bearing has. > >Ah. Thanks. Didn't see that. > > >In the definition of 'h' you say: > >> When a relative *h* command is used, the end point of the line is >(cpx + x > cos cb, cpy + x sin cb). > >Given that the cpx,cpy moves, I assume that means that you can use "b >90 h >10 10 10 z" to draw a square? The bearing needs to be set again after each segment though so it would be "M 100,100 h 10 b 90 h 10 b 90 h 10 z". >>Although multiple parameters may be specified, this usually will not >be >useful, as they could be combined into a single angle value. > >I'm not sure about the clarity of this statement. For example, does >the >following draw a pentagon or not? > > "b 36 36 h 47 47 47 47 z" It's equivalent to "b 72 h 47 47 47 47 z" but as I say above you need a b between each h. The bearing is only changed by a B or b command. If you're writing a path with a curve to you could add a "b 0" after it to set the bearing to be at a tangent to the end of the curveto, for example. >And is the following equivalent to your pentagon example or not? > > "M 150,10 b -36 72 h 47 47 47 47 z" No.
Received on Thursday, 13 February 2014 09:56:27 UTC