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Percentage lengths in SVG 1.1 sec 7.10

From: Alan Stearns <stearns@adobe.com>
Date: Fri, 20 Jul 2012 11:51:18 -0700
To: "www-svg@w3.org" <www-svg@w3.org>
Message-ID: <CC2EF6B6.13278%stearns@adobe.com>
Hey all,

There's a typo in section 7.10 in the formula for percentage lengths that
are not heights or widths. It's just an extra parenthesis before the
slash. So it should read:

sqrt((actual-width)**2 + (actual-height)**2)/sqrt(2)

But I'm also wondering what motivates this particular formula. I'm looking
at how a percentage value for the radius of a circle works. In a square
10x10 viewport it's a percentage of 10, which makes sense. You're getting
the length of the diagonal divided by the square root of 2, which gets you
back to height or width.

In a 20x10 rectangle, you get a percentage of 15.81. I don't understand
how that's useful in this case. You have the length of the diagonal on top
again, but how is the square root of 2 relevant for non-square viewports?
Is there a non-radius use case for percentage lengths in rectangles where
this result is useful, or was this formula chosen mainly to make a square
viewport work as expected?


Received on Friday, 20 July 2012 18:51:48 UTC

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