- From: ___ <berlusconigay@gmail.com>
- Date: Sat, 16 Jun 2007 23:56:34 +0200
- To: "'SMIL List'" <www-smil@w3.org>
This situation is extremely easy to understand, please give me a reply
please. I'm using real player.
<body>
<par dur="indefinite">
<par id="A_par" begin="bt_A.activateEvent" end="bt_B.activateEvent">
......
</par>
<par id="B_par" begin="bt_B.activateEvent" end="bt_A.activateEvent">
<par id="B_par_text1" begin="0s;arrow_b.activateEvent"
end="B_par.end;arrow_f.activateEvent">
<textstream id="B_text1" src="..."
rn:backgroundOpacity="0%" transIn="fade_1" region="text_B_a"
end="B_par_text1.end;bt_A.activateEvent" fill="freeze"/>
<textstream id="B_text2" src="..."
rn:backgroundOpacity="0%" transIn="fade_1" region="text_B_b"
end="B_par_text1.end;B_par.end" fill="freeze"/>
</par>
<par id="B_par_text2" begin="arrow_f.activateEvent"
end="B_par.end;arrow_b.activateEvent">
.......
</par>
</par>
</par>
</body>
</smil>
Why when B_text1 and B_text2 are visible, and i click on bt_A, only B_text1
disappear?
The difference between B_text1 and B_text2 is that the end differ in this
way:
B_text1 --> B_par_text1.end;bt_A.activateEvent
B_text2 --> B_par_text1.end;B_par.end
BUT, since B_par group has the end attribute set to: bt_A.activateEvent,
shouldn't B_par.end and bt_A.activateEvent act the SAME way?
No virus found in this outgoing message.
Checked by AVG Free Edition.
Version: 7.5.472 / Virus Database: 269.8.17/850 - Release Date: 15/06/2007
11.31
Received on Saturday, 16 June 2007 21:57:02 UTC