RE: rdfs:Property rdfs:range questions

> But there is no way to define the property p
> *using only the RDF and RDFS vocabulary*,
> such that the RDF Model thory would entail
> {ex:b rdf:type ex:R.}
> from
> {ex:p rdfs:range ex:R. ex:a ex:p ex:b.},
> is there ?

I don't quite understand. <ex:p> <rdfs:range> <ex:R>. <ex:a> <ex:p> <ex:b>.
already entails <ex:b> <rdf:type> <ex:R>. when you produce an RDFS closure,
what else do you need?

http://www.w3.org/TR/rdf-mt/#rdfs_entail - step 3 rule rdfs3.

Received on Friday, 20 September 2002 09:37:06 UTC