- From: Benoit Mahe <Benoit.Mahe@sophia.inria.fr>
- Date: Fri, 30 Apr 1999 16:56:34 +0200
- To: Luc Saint-Elie <lse@imaginet.fr>
- CC: www-jigsaw@w3.org
Luc Saint-Elie wrote:
> Well lucky you, its time for our regular feature "the stupid question of
> the day"
>
> How does Jigsaw handle the path under windows 98 ?
>
> I have a path to set up for a servlet properties.
Ok, but what do you do with this path? new File(), getResource()?
If you are using getResource
URL url = getClass().getClassLoader().getResource("cocoon.properties")
should works. This is relative to the servlet directory.
Regards, Benoit.
> In fact the servlet is a
> .jar file so I have set up the servlet wrapper.
> My jar file is in c:\jdk\jre\lib\ext
> I have no problem to access it.. but it has a big problem in accessing the
> properties file
>
> In this case is the path :
> - relative to the JDK path (in my case the jdk\jre\lib\ext directory ?
> - relative to my Jigsaw install directory ?
> - relative to my Jigsaw\jigsaw\www\servlet directory ?
>
> And how is this parth (the path I have to enter in the servlet properties
> dialog) spelled
>
> The physical file path is d:\jigsaw\jigsaw\www\servlet\cocoon.properties
>
> do I need to use unix bakslah ? double slash ?....
>
> Thanks in advance
> +------------------------------------------------+
> | Luc Saint-Elie |
> | 53, rue Caulaincourt |
> | 75018 Paris France |
> | Tel: 01 42 52 09 62 / 06 12 90 19 65 |
> | email : luc@interpasnet.com |
> +------------------------------------------------+
> | Servlet Taverne a site devoted to servlets |
> | ..and Java server side technologies |
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> | url : http://www.interpasnet.com/JSS |
> +------------------------------------------------+
--
- Benoît Mahé -------------------------------------------------------
World Wide Web Consortium (W3C)
Architecture domain - Jigsaw Engineer
http://www.w3.org/People/Mahe - bmahe@w3.org
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Received on Friday, 30 April 1999 10:56:42 UTC