Re: Help with simple SPARQL query getting strings of selected languages

> On Mar 22, 2018, at 8:45 AM, Mikael Pesonen <mikael.pesonen@lingsoft.fi> wrote:
> 
> 
> Hi,
> 
> I'm having trouble contructing a basic query which selects a string so that it prefers one language, over others but always tries to return something.
> 
> So I have names
> 
> :item schema:name "name"@en
> :item schema:name "nimi"@fi
> :item schema:name "namn"
> 
> I need query that returns the English name ("name"@en) , but if not found the name without language ("namn"), and as last resort name in Finnish ("nimi"@fi)
> 
> This query returns one random name:
> 
> SELECT
> ?s
> (SAMPLE(?s_label_g) as ?s_label)
> ?s_type
> FROM <http://some_graph/>
> WHERE
> {
>     ?s a ?s_type .
>     ?s <http://schema.org/name> ?s_label_g
> }
> GROUP BY ?s ?s_type
> 
> 
> Anyone can help?


Mikael,

You can use OPTIONAL to do this by ordering the optional blocks by the preferred language tags:

SELECT ?s ?s_label ?s_type
WHERE {
    ?s a ?s_type .
    OPTIONAL { ?s <http://schema.org/name> ?s_label . FILTER(LANGMATCHES(LANG(?s_label), "en")) }
    OPTIONAL { ?s <http://schema.org/name> ?s_label . FILTER(LANG(?s_label) = "") }
    OPTIONAL { ?s <http://schema.org/name> ?s_label . FILTER(LANGMATCHES(LANG(?s_label), "fi")) }
}

If you want to fall back on *any* language for cases where there is no English, Finnish, or un-tagged literal, you can also add a fourth optional block to the end:

SELECT ?s ?s_label ?s_type
WHERE {
    ?s a ?s_type .
    OPTIONAL { ?s <http://schema.org/name> ?s_label . FILTER(LANGMATCHES(LANG(?s_label), "en")) }
    OPTIONAL { ?s <http://schema.org/name> ?s_label . FILTER(LANG(?s_label) = "") }
    OPTIONAL { ?s <http://schema.org/name> ?s_label . FILTER(LANGMATCHES(LANG(?s_label), "fi")) }
    OPTIONAL { ?s <http://schema.org/name> ?s_label . }
}

Hope that helps.

.greg

Received on Thursday, 22 March 2018 14:13:14 UTC