Re: Processiing arrays in XSLT 4

On Tue, 12 Jan 2021 at 13:04, Michael Kay <mike@saxonica.com> wrote:

> Yes, that's right (I had already spotted it but didn't want to trouble
> anyone...)
>
> I think we can also allow <xsl:for-each map="$map"> creating items
> accessible as .?key and .?value. I've tried a few JSON-to-XML examples and
> it works quite nicely, including (probably) for grouping.
>

I like this approach for both arrays and maps.


> I think the keywords array="X" and map="Y" work OK, rather that say
> element-in-array or entry-in-map. After all, X is an array and Y is a map.
> It would ideally be
>
> <xsl:for-each-in array="X">
>
> but we don't want to change the instruction name.
>
> Or we could do
>
> <xsl:for-each in-array="X">
>
> but it feels like unnecessary noise.
>

If we are going for consistency with the XPath/XQuery proposal then this
could be member="..." that accepts an array or map. I'm happy either way
(@array/@map or @member).

Kind regards,
Reece


> Michael Kay
> Saxonica
>
> > On 12 Jan 2021, at 12:38, Martin Honnen <martin.honnen@gmx.de> wrote:
> >
> >
> > On 12.01.2021 12:27, Martin Honnen wrote:
> >>
> >> On 12.01.2021 11:25, Michael Kay wrote:
> >>> Mindful of DImitre's exhortation to avoid growing the language any
> >>> more than is necessary, I propose the following:
> >>>
> >>> * xsl:for-each, xsl:iterate, and xsl:for-each-group acquire an
> >>> attribute array=expression which can be used instead of
> >>> select=expression
> >>>
> >>> * specifying array="EXPR" is equivalent to specifying
> >>> select="array:for-each(EXPR, function($x){map{'value': $x})"/>
> >
> >
> > Is that meant as
> >
> >    select="array:for-each(EXPR, function($x){map{'value': $x}})?*"
> >
> > ?
> >
> >>>
> >>> The effect is that you iterate over the members of the array, and
> >>> that you can refer to the current member of the array as .?value. The
> >>> position of the member within the array is available as position().
> >>>
> >>>
> >>
> >> Does that work with for-each-group where inside of the instruction
> >> position() is supposed to give you the position of the current group and
> >> not the position of the item in the grouping population?
> >>
> >> Or how does grouping work if the population is a (single?) array created
> >> by array:for-each?
> >>
> >>
> >
>
>
>