Re: Processiing arrays in XSLT 4

> 
> Surely, there is even no need to iterate at all, if we have the syntax below:
> 
> <xsl:array member-source="*"  member-generator="my:mapHistory"/> 
> 
> Here, the XSLT processor is calling my:mapHistory() once for every item in member-source, and the result of the call is the corresponding, Nth member of the array. 
> 

This feels very counter-intuitive to me. Perhaps you could flesh out the use case I supplied to see what the full solution looks like.

Michael Kay
Saxonica

Received on Saturday, 9 January 2021 23:18:39 UTC