Re: [webrtc-pc] Regarding "a=msid"

I like option 1. or 2. here. We need "a=msid ..." lines to signal that a given sender/track is associated with a given MediaStream ID.

>  No calls to "Create an RTCRtpReceiver" actually pass an ID as an argument
Do you mean a track ID or stream ID? It seems to me that we can't currently rely on track ID, but the stream ID can still be useful. Is that correct? In that case I would prefer to either allow duplicates or just generate a random track ID if there is a duplicate (as opposed to generating a random stream ID).

Do we know why duplicates aren't allowed?


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Received on Thursday, 11 October 2018 18:09:06 UTC