- From: Jake Archibald <notifications@github.com>
- Date: Thu, 31 Mar 2016 09:02:15 -0700
- To: slightlyoff/ServiceWorker <ServiceWorker@noreply.github.com>
Received on Thursday, 31 March 2016 16:02:46 UTC
> Shouldn't it be the expected behaviour? No, it would break sites if V1 starts getting V2's assets. If I explicitly wanted this behaviour, I could delete the old cache, but I've never wanted that behaviour. > If developers are afraid of breaking the page, then why don't they use Cache.match instead? You could also do that to get the latest version. If you really want a reverse cache search, here it is: ```js function reverseCacheSearch(request) { return caches.keys().then(cacheNames => { return cacheNames.reverse().reduce((chain, cacheName) => { return chain.then(response => { return response || cache.open(cacheName).then(c => c.match(request)); }) }, Promise.resolve()) }) } ``` In most cases, you may even get away with: ```js caches.matchAll(request).then(r => r && r[r.length-1]); ``` --- You are receiving this because you are subscribed to this thread. Reply to this email directly or view it on GitHub: https://github.com/slightlyoff/ServiceWorker/issues/862#issuecomment-204000116
Received on Thursday, 31 March 2016 16:02:46 UTC