- From: Mihai Sucan <mihai.sucan@gmail.com>
- Date: Wed, 14 Jun 2006 12:15:06 +0300
- To: "David Arthur" <mumrah@gmail.com>, public-webapi@w3.org
Le Tue, 13 Jun 2006 23:29:28 +0300, David Arthur <mumrah@gmail.com> a
écrit:
> how about a retry method?
>
> so maybe one could do this.
>
> xhr.open("GET",url,true);
>> xhr.onreadystatechange = function(){
>> if(xhr.readyState == 4 && xhr.status == 408)
>> {
>> //code for timeout
>> xhr.retry();
>> }
>> xhr.send(null);
+1
I like the idea. It can prove useful in situations when the user
experiences a short network hiccup.
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Received on Wednesday, 14 June 2006 09:15:12 UTC