Re: clip-path contradiction

Erik Dahlstrom:
> in the definition of the 'clipPath' element[1] it's stated that you
> can apply the 'clip-path' property to a 'clipPath' element and that
> the result is the intersection of the two clip paths. However, in
> the 'clip-path' property definition the 'clipPath' element isn't
> listed as one of the elements to which 'clip-path' applies to. I
> think it should be added there.

Yes, I think so.  Note that in SVG 1.1 First Edition clipPath was
defined to be a container element.  I think that it was removed from
that list because that implied certain other requirements on clipPath
that didn’t make sense (though I don’t remember what these were now).

-- 
Cameron McCormack ≝ http://mcc.id.au/

Received on Wednesday, 17 November 2010 22:22:37 UTC