- From: Hanane Ouksili <hanane.ouksili@gmail.com>
- Date: Tue, 7 Jul 2015 13:21:38 +0200
- To: public-sparql-dev@w3.org
- Message-ID: <CALTw2KkYOCiGiukK5gTcwmW1B=SLOKdCNMPMdKsDZ9K1N2aLww@mail.gmail.com>
Dear all,
I have the following question:
In the previous version of SPRQL I was using the CONSTRUCT clause to
extract the graph part of a KB.
This feature does not seam to work in the SPARQL 1.1. when i use the Path
Language
For example,
CONSTRUCT
{ ?x (^rdfs:subClassOf)*/^rdf:type ?y }
WHERE {
?x (^rdfs:subClassOf)*/^rdf:type ?y
}
I want, by this query to extract the path between ?x and ?y when it is
egale to (^rdfs:subClassOf)*/^rdf:type. This query work with the SELECT
clause but no with the CONSTRUCT clause
Can you please tell me if I do something wrong or if there is an other
solution to do that in SPARQL 1.1?
Thank you in advance,
On Tue, Jul 7, 2015 at 1:14 PM, Hanane Ouksili <hanane.ouksili@gmail.com>
wrote:
> Dear all,
>
> I have the following question:
>
> In the previous version of SPRQL I was using the CONSTRUCT clause to
> extract the graph part of a KB.
>
> This feature does not seam to work in the SPARQL 1.1. when i use the
> Path Language
>
> Can you please tell me if I do something wrong or if there is
>
> --
>
>
>
>
>
>
>
>
> * Hanane OUKSILIDoctorante - Laboratoire PRiSM Université de
> Versailles-St-Quentin-en-Yvelines- EDF - R&DDépartement STEP Chatou *
>
--
* Hanane OUKSILIDoctorante - Laboratoire PRiSM Université de
Versailles-St-Quentin-en-Yvelines- EDF - R&DDépartement STEP Chatou
hanane.ouksili@gmail.com <hanane.ouksili@gmail.com> tél 00336 49 69 43 03*
Received on Tuesday, 7 July 2015 14:12:01 UTC