- From: Sean Hogan <shogun70@westnet.com.au>
- Date: Thu, 06 Jun 2013 00:41:41 +1000
- To: Anne van Kesteren <annevk@annevk.nl>
- CC: Sam Tobin-Hochstadt <samth@ccs.neu.edu>, "Tab Atkins Jr." <jackalmage@gmail.com>, "Mark S. Miller" <erights@google.com>, "www-dom@w3.org" <www-dom@w3.org>, "public-script-coord@w3.org" <public-script-coord@w3.org>, Alex Russell <slightlyoff@google.com>
On 4/06/13 11:48 PM, Anne van Kesteren wrote: > On Tue, Jun 4, 2013 at 8:55 AM, Sam Tobin-Hochstadt <samth@ccs.neu.edu> wrote: >> Thinking about this more, I'm now unsure why both `fulfill` and >> `resolve` are needed given the semantics of `.chain()` and `.then()` >> described below. >> >> In particular, if `.then()` chains recursively *before* calling the >> callback, then there's no difference between: >> >> Future.resolve(x).then(v => ...) >> >> and >> >> Future.fulfill(x).then(v => ...) >> >> even when `x` is a promise. The only way to observe this is with `.chain()`. >> >> Thoughts? > I'm just going to try to repeat what you said here to make sure I understand. > > Promise.resolve(val) creates a promise of val, regardless of whether > val is a promise, has a callable then property, or anything like that. > (In that sense it is equivalent to Future.accept() today.) > > promise.then() keeps unwrapping promise's internal value until it no > longer has a callable then property at which point it invokes the > relevant callback passed to promise.then(). (Exact algorithm TBD after > broader agreement.) > > promise.chain() invokes its relevant callback with promise's internal value. > > promise.then() and promise.chain() return value (newPromise) is > resolved with the return value of their callbacks after it has been > unwrapped once. What is the algorithm for this single unwrapping which is done to the return value of .then() / .chain() callbacks? Is it something like: Assuming the return value from the callback (result) is to be conditionally unwrapped and then fulfil the future (f) with associated resolver (r): function unwrap(result, f, r) { if (result && typeof result.chain === 'function') result.chain(accept, reject); else if (result && typeof result.then === 'function') result.then(accept, reject); else accept(result); function accept(val) { r.accept(val); } function reject(err) { r.reject(val); } } Or should 'chain-ables' be restricted to `result instanceof Future`? Can .chain() be called with missing accept/reject callbacks? e.g. .chain(null, function(err) { throw err; }); What is the behavior of the default accept / reject callbacks in this case?
Received on Wednesday, 5 June 2013 14:42:12 UTC