- From: Sean Hogan <shogun70@westnet.com.au>
- Date: Thu, 06 Jun 2013 00:41:41 +1000
- To: Anne van Kesteren <annevk@annevk.nl>
- CC: Sam Tobin-Hochstadt <samth@ccs.neu.edu>, "Tab Atkins Jr." <jackalmage@gmail.com>, "Mark S. Miller" <erights@google.com>, "www-dom@w3.org" <www-dom@w3.org>, "public-script-coord@w3.org" <public-script-coord@w3.org>, Alex Russell <slightlyoff@google.com>
On 4/06/13 11:48 PM, Anne van Kesteren wrote:
> On Tue, Jun 4, 2013 at 8:55 AM, Sam Tobin-Hochstadt <samth@ccs.neu.edu> wrote:
>> Thinking about this more, I'm now unsure why both `fulfill` and
>> `resolve` are needed given the semantics of `.chain()` and `.then()`
>> described below.
>>
>> In particular, if `.then()` chains recursively *before* calling the
>> callback, then there's no difference between:
>>
>> Future.resolve(x).then(v => ...)
>>
>> and
>>
>> Future.fulfill(x).then(v => ...)
>>
>> even when `x` is a promise. The only way to observe this is with `.chain()`.
>>
>> Thoughts?
> I'm just going to try to repeat what you said here to make sure I understand.
>
> Promise.resolve(val) creates a promise of val, regardless of whether
> val is a promise, has a callable then property, or anything like that.
> (In that sense it is equivalent to Future.accept() today.)
>
> promise.then() keeps unwrapping promise's internal value until it no
> longer has a callable then property at which point it invokes the
> relevant callback passed to promise.then(). (Exact algorithm TBD after
> broader agreement.)
>
> promise.chain() invokes its relevant callback with promise's internal value.
>
> promise.then() and promise.chain() return value (newPromise) is
> resolved with the return value of their callbacks after it has been
> unwrapped once.
What is the algorithm for this single unwrapping which is done to the
return value of .then() / .chain() callbacks? Is it something like:
Assuming the return value from the callback (result) is to be
conditionally unwrapped and then fulfil the future (f) with associated
resolver (r):
function unwrap(result, f, r) {
if (result && typeof result.chain === 'function')
result.chain(accept, reject);
else if (result && typeof result.then === 'function')
result.then(accept, reject);
else accept(result);
function accept(val) { r.accept(val); }
function reject(err) { r.reject(val); }
}
Or should 'chain-ables' be restricted to `result instanceof Future`?
Can .chain() be called with missing accept/reject callbacks? e.g.
.chain(null, function(err) { throw err; });
What is the behavior of the default accept / reject callbacks in this case?
Received on Wednesday, 5 June 2013 14:42:12 UTC