Re: [Core](PRD] safeness

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Gary Hallmark <gary.hallmark@oracle.com> wrote on 09/06/2009 22:54:27:
> 
> R1: if not(P(?x) and ?x=1) then Q(1)
> 
> I claim R1 is safe because ?x is bounded and used only "inside the not".

No, R1 is not safe either, I think; because x can be bound to anything 
(any x!=1 satisfies the condition, independent of P).

Christian


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Received on Wednesday, 10 June 2009 09:05:39 UTC