Re: para termination

On 25 November 2012 12:46, Ryan Freebern <rfreebern@unionstmedia.com> wrote:
> On Sun, Nov 25, 2012 at 5:13 AM, Dave Pawson <dave.pawson@gmail.com> wrote:
>>
>> On 24 November 2012 18:39, Ryan Freebern <rfreebern@unionstmedia.com>
>> wrote:
>> >
>> > In my opinion, the para definition should be:
>> >
>> > 0 to 3 space characters, arbitrary text, then EOF or (a newline
>> > character
>> > followed by a blank line).
>>
>> Clarification if I may. Do you agree
>> \s{0-3} arbitrary text termination.
>>
>> Testing with currentMD,
>> it would appear that termination can consist of
>> \n\n   | \ws+\n |\nEOF | \ws+EOF|EOF
>>
>> where ws is 0x20 |  0x9, I.e. any number of white space characters,
>> (or the 'empty line').
>
>
> Further clarification. I think you mean:
>
> \n\n | \n\ws+\n | \nEOF | \n\ws+EOF | EOF
>
> which can be shortened to
>
> \n\ws*\n | \n\ws*EOF | EOF
>
>
> Is this correct?

<chuckles/> Yes. I'll go with that and add it.

Thanks Ryan.

aside. The inclusion of 'blank lines' is really messy with lists. More
later on this.



-- 
Dave Pawson
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http://www.dpawson.co.uk

Received on Sunday, 25 November 2012 12:50:31 UTC