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RE: NEW issue 6 - defining semantic relationships

From: Charles McCathieNevile <charles@w3.org>
Date: Tue, 18 Nov 2003 21:56:49 -0500 (EST)
To: "Miles, AJ (Alistair) " <A.J.Miles@rl.ac.uk>
Cc: 'Dave Reynolds' <der@hplb.hpl.hp.com>, "'public-esw-thes@w3.org'" <public-esw-thes@w3.org>
Message-ID: <Pine.LNX.4.55.0311182155590.303@homer.w3.org>

If they really are the same thing, why not just stop using them, since the
rdfs: stuff is likely to be understood by tools already?

cheers

Chaals

On Tue, 18 Nov 2003, Miles, AJ (Alistair)  wrote:

>
>OK, so shall we have
>
>
><soks:semanticRelation>
>^
>|
><soks:broader>
>^                        ^                           ^
>|                        |                           |
><soks:broaderGeneric>    <soks:broaderInstantive>    <soks:broaderPartOf>
>
>and
>
><soks:broaderGeneric>   <owl:equivalentProperty>   <rdfs:subClassOf>.
>
><soks:broaderInstantive>   <owl:equivalentProperty>   <rdf:type>.
>
>Any objections???
>
>Al.
>
>> >
>> > ... would be good for thesaurus-specific applications.
>> However, here is
>> > where we start treading on the toes of RDF RDFS and OWL.
>> The property
>> > <thes:broaderGeneric> would be semantically equivalent to
>> <rdfs:subClassOf>,
>> > and the property <thes:broaderInstantive> would be
>> semantically equivalent
>> > to <rdf:type>.  How do we handle this kind of overlap?
>>
>> I'm not sure there is a problem here. If BG and BI are truly
>> equivalent to
>> rdfs:subClassOf and rdf:type then just define them as
>> equivalent using
>> either owl:equivalentProperty or a pair of rdfs:subPropertyOf
>> relations.
>> That's the beauty of RDF - open world, multiple inheritance,
>> cycles allowed.
>>
>> Then a thesaurus processor could take an RDFS file and realise, for
>> example, that an rdfs:subClassOf relation implies thes:broader.
>>
>> Dave
>>
>

Charles McCathieNevile  http://www.w3.org/People/Charles  tel: +61 409 134 136
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Received on Tuesday, 18 November 2003 21:57:14 UTC

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