- From: Holger Knublauch <holger@topquadrant.com>
- Date: Fri, 11 Mar 2016 16:03:34 +1000
- To: "public-data-shapes-wg@w3.org" <public-data-shapes-wg@w3.org>
On 11/03/2016 15:27, Peter F. Patel-Schneider wrote: > > On 03/10/2016 08:37 PM, Holger Knublauch wrote: >> On 11/03/2016 13:22, Peter F. Patel-Schneider wrote: >>> On 03/10/2016 06:04 PM, Holger Knublauch wrote: >>>> On 10/03/2016 1:17, Peter F. Patel-Schneider wrote: >>>>> On 03/09/2016 12:46 AM, Holger Knublauch wrote: >>>>>> On 9/03/2016 18:17, Peter F. Patel-Schneider wrote: >>>>>>> I'm pretty sure that this fails in a number of places. > [...] >>>>>>> The substitution can modify variables from different scopes, which will >>>>>>> change >>>>>>> results. >>>>>> Do you have an example for this? >>>>> SELECT ?this ?that >>>>> WHERE { ?this ex:a ex:b >>>>> SELECT ?that WHERE { ?this ex:a ?that } } >>>> The definition states that substitution also happens in nested SELECTs. I >>>> believe this meets user expectations, and would be needed for cases like >>>> sh:minCount that use a nested SELECT. I don't quite see a problem with the >>>> above. Do you have data to illustrate why this would cause problems? >>> Because the ?this in the inner SELECT is a different variable. Before >>> substitution it would return any ?that that is the object of any ex:a triple. >>> After substitution it returns only those that have the substituted value as a >>> subject. >> Yes, but that is exactly the desired outcome. >> >> Holger > I'm not a SPARQL expert, but I don't think so. > > > Let's pre-bind ?this to ex:c (this is a very easy case of pre-binding, so > what to do is pretty obvious) in > > SELECT ?this ?that > WHERE { ?this ex:a ex:b . > SELECT ?that WHERE { ?this ex:a ?that } } > > against graph > > ex:c ex:a ex:b . > ex:c ex:a ex:b . > ex:d ex:a ex:f . What is this "duplicate" triple above (first two lines)? Did you mean ex:c ex:a ex:f ? Holger > > The result set is > ?this = ex:c, ?that = ex:b > ?this = ex:c, ?that = ex:f > > Let's substitute ?this by ex:c to get (roughly) > > SELECT (ex:c AS ?this) ?that > WHERE { ex:c ex:a ex:b . > SELECT ?that WHERE { ex:c ex:a ?that } } > > which results in only one solution > ?this = ex:c, ?that = ex:b > > peter > > > > > > > > > >
Received on Friday, 11 March 2016 06:04:09 UTC