- From: Tab Atkins Jr. via GitHub <sysbot+gh@w3.org>
- Date: Mon, 03 Feb 2020 23:04:59 +0000
- To: public-css-archive@w3.org
Yup, my brain was assuming nearest there. `round(up 1, ∞)` should definitely return ∞. > Also, returning 0 for an infinite precision seems to imply that 0 is a multiple of infinity. But 0 * ∞ = NaN, not 0. This makes me a bit uneasy, though I guess it's fine if you consider limits. Yes, you usually have to consider the limit behavior for infinities; `round(1, very-large-finite-number)` definitely rounds to zero, so infinity should act the same. On the other hand... > Say that round(strategy, A, ±∞) is always NaN. This works for me too. I don't think this is an important case to care about. -- GitHub Notification of comment by tabatkins Please view or discuss this issue at https://github.com/w3c/csswg-drafts/issues/4725#issuecomment-581662223 using your GitHub account
Received on Monday, 3 February 2020 23:05:01 UTC