Re: Node lifetime question

Agreed with Raymond here.

Paul.

On Tue, Oct 4, 2016 at 12:20 AM, Raymond Toy <rtoy@google.com> wrote:

> Once oscB has stopped, and because you've dropped all references to both A
> and B, does it matter anymore?  Nothing is observable anymore and you can't
> make them observable, so it seems to me we don't have to say anything.  The
> implementation can do whatever it wants now.
>
> On Mon, Oct 3, 2016 at 8:04 AM, Joe Berkovitz <joe@noteflight.com> wrote:
>
>> But in that case, A and B both have "playing" references as per the
>> Lifetime section of the spec, so JS references are irrelevant.
>>
>> So here is an improved and hopefully more troubling statement of the
>> question:
>>
>> Let's say that osc A is modulating the frequency of osc B, but that B
>> reached its stop time (and A has no stop time). Would we keep B alive
>> anyway, because retained node A is modulating it, in spite of the fact that
>> B can only produce silence?
>>
>> Example:
>>   var oscA = new OscillatorNode(...);
>>   var oscB = new OscillatorNode(...);
>>   oscA.connect(oscB.frequency);
>>   oscB.connect(ctx.destination);
>>   oscA.start();
>>   oscB.start();
>>   oscB.stop(ctx.currentTime + 1);
>>   oscA = oscB = null;
>>
>>
>> .            .       .    .  . ...Joe
>>
>> Joe Berkovitz
>> President
>> Noteflight LLC
>>
>> +1 978 314 6271
>>
>> 49R Day Street
>> Somerville MA 02144
>> USA
>>
>> "Bring music to life"
>> www.noteflight.com
>>
>> On Fri, Sep 30, 2016 at 7:18 PM, Raymond Toy <rtoy@google.com> wrote:
>>
>>> I think it should.  If A and B are both oscillators and A is connected
>>> to, say, B.frequency, I expect to hear the modulated B even if A and B have
>>> no Javascript references to them.
>>>
>>> On Fri, Sep 30, 2016 at 1:22 PM, Joe Berkovitz <joe@noteflight.com>
>>> wrote:
>>>
>>>> I sat down to work on https://github.com/WebAudio/we
>>>> b-audio-api/issues/944 and discovered a question.
>>>>
>>>> So: we already know (I think) that when AudioNode A's output is
>>>> connected to AudioNode B's input, then A has a "connection reference" to B.
>>>> Thus, if A is retained, B is retained too.
>>>>
>>>> But what about the case where AudioNode A is connected to an AudioParam
>>>> exposed by AudioNode B? Does A keep B alive in this case?
>>>>
>>>> .            .       .    .  . ...Joe
>>>>
>>>>
>>>
>>
>