Re: Question about section 5.4 ... 0 in bit 5 means uppercase?

Bits are numbered 0..7 from the right, so E == hex 45 == 0100 0101 has a 0
in bit 5 (and e == hex 65 == 0110 0101 has a 1).

On Fri, Jul 1, 2016 at 1:44 PM, Costello, Roger L. <costello@mitre.org>
wrote:

> Hi Folks,
>
> In section 5.4 Chunk Naming Conventions it says:
>
>         Four bits of the chunk type, the property bits, namely
>         bit 5 (value 32) of each byte, are used to convey chunk
>         properties. This choice means that a human can read
>         off the assigned properties according to whether the
>         letter corresponding to each byte of the chunk type is
>         uppercase (bit 5 is 0) or lowercase (bit 5 is 1).
>
> I think the second sentence is saying (or implying) that every uppercase
> ASCII letter has 0 in bit 5. But that is not true; for example, E is hex 45
> (0100 0101), which means it has 1 in bit 5.
>
> Either I am misunderstanding the second sentence (most likely) or it is a
> false statement.
>
> Please advise.
>
> /Roger
>
>
>
>