RE: Header compression question: duplicate header entry and current index on computing working set

How did the object get into the reference set?  Because the compressor referenced an object by index, or included it as a literal and added it to the table.

So the object in the reference set points to the entry in the table it was added with.  If there happens to be another identical entry in the table, nothing says that the decompressor will even notice that.  I don't recall anything that requires the decompressor to sweep the header table looking for matches - that's the compressor's job.

From: Tatsuhiro Tsujikawa [mailto:tatsuhiro.t@gmail.com]
Sent: Wednesday, July 17, 2013 9:52 AM
To: Martin Thomson
Cc: ietf-http-wg@w3.org
Subject: Re: Header compression question: duplicate header entry and current index on computing working set



On Thu, Jul 18, 2013 at 1:36 AM, Martin Thomson <martin.thomson@gmail.com<mailto:martin.thomson@gmail.com>> wrote:
On 17 July 2013 08:56, Tatsuhiro Tsujikawa <tatsuhiro.t@gmail.com<mailto:tatsuhiro.t@gmail.com>> wrote:
> In 3.4, to compute working set from reference set of headers, the index of
> entry in header table is required.
> The question is, when the duplicate entries are in the header table, which
> index is used as the index of working set?
If, for some strange reason, a compressor created multiple identical
entries in the table, the decompressor is required to respect that
choice, even if it is likely to be a bug.  This prevents the
decompressor and compressor from getting out of sync.

The compressor can then reference any of the entries when using an index.

If the choice is arbitrary, then the compressor and decompressor may choose different index and
can get out of sync.

For example,
Current header table:
|0|name1|value1|
|1|name1|value1|

If name1/value1 is in reference set, compressor chooses index 0, and decompressor chooses index 1.
compressor wants to remove name1/value1, so reference index 0.
In decompressor side, however, seeing index header representation with index 0 and it is not in its reference set
(because name1/value1 is index 1), retrieve index 0 from header table and add it to working set.
Maybe I misunderstand the draft.

If multiple identical entries are considered as a bug, then it would be better to
prohibit it in the spec and we are happy to not to consider these things.

Best regards,

Tatsuhiro Tsujikawa

Received on Wednesday, 17 July 2013 17:00:59 UTC