Re: Although no external representation of schemas is required ... What is an "external" representation?

In addition to whatever datatype components may be built in, one of the use 
cases we discussed was one in which an XHTML editor might have built in 
knowledge of a schema for XHMTL. Nothing precludes a special-purpose editor 
of other industry standard vocabularies from building in knowledge of the 
validation rules for those vocabularies.

Noah

On 6/28/2012 12:37 PM, David Ezell wrote:
> Yes, this was exactly the intention.  And some of the discussions around the issue use the term "born binary" to mean schemas that are encoded into a processor, with no "external" XML representation ever actually having existed.
>
> -----Original Message-----
> From: G. Ken Holman [mailto:gkholman@CraneSoftwrights.com]
> Sent: Thursday, June 28, 2012 8:23 AM
> To: xmlschema-dev@w3.org
> Subject: Re: Although no external representation of schemas is required ... What is an "external" representation?
>
> At 2012-06-28 12:15 +0000, Costello, Roger L. wrote:
>> In section 3.1.2 of the Structures specification it says:
>>
>>      Although no external representation of schemas
>>      is required ...
>>
>> What is an "external" representation of an XML Schema?
>
> Typically XML Schema syntax in XML (though I gather there are some experiments out there with alternative syntaxes).
>
>> External to what?
>
> The schema processor.
>
>> What is a non-external (internal?) representation of an XML Schema?
>> Do such things exist?
>
> They can.  As a convenience a processor can build-in the schema components of a given namespace such that the user need not have to supply an external expression of those schema components.
>
> I don't know any that do, just because I haven't looked, but it is certainly possible for a processor to offer this.
>
> I hope this helps.
>
> . . . . . . . . . . Ken
>
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Received on Thursday, 28 June 2012 21:58:00 UTC