From: xmlplus custodians <xmlplus.custodians@gmail.com>

Date: Sun, 10 Apr 2011 02:19:31 +0530

Message-ID: <BANLkTimuk5Ca8k9F+RLjzpr982JG+qA=eA@mail.gmail.com>

To: xmlschema-dev@w3.org

Date: Sun, 10 Apr 2011 02:19:31 +0530

Message-ID: <BANLkTimuk5Ca8k9F+RLjzpr982JG+qA=eA@mail.gmail.com>

To: xmlschema-dev@w3.org

Hi The XSD1.1 DataTypes spec in the base64Binary section gives following pseudo-code for calculating octet length of a base64Binary encoded string. --------------------------------------------------------------------------------- 1) lex2 := killwhitespace(lexform) -- remove whitespace characters 2) lex3 := strip_equals(lex2) -- strip padding characters at end 3) length := floor (length(lex3) * 3 / 4) -- calculate length --------------------------------------------------------------------------------- My understanding is that, for a base64Binary encoded string, it's lexical length would be a multiple of 4 and it's octet length would be a multiple of 3. As an example if we take a base64Binary encoded string, which doesn't contain whitespaces or padding chars(=), so that lexform is same as lex3 in above code. Now let us take a lex3 of length 10 then, according to above code, the octet length would be 7(not a multiple of 4). Are octet-lengths which are not multiple of 4, valid in case of base64Binary encoded string ? Also, what should be the formulae for calculating lexical-length from the octet-length of a base64Binary string ? Should it be something like this: * * *lexical-length := ceil( octet-length*4/3)* If we take an example with octet-length=10, the lexical-length is not a multiple of 4. I am clueless here. Appreciate your help on the same. -- Best Regards, Satya Prakash TripathiReceived on Saturday, 9 April 2011 20:49:58 UTC

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