Re: Changing "substitutionGroup" to "choice" and maintaining the validation equality of the schema

Sorry to be _very_ slow to reply to this one.

Your translations:

"Marko Smiljanic" <m.smiljanic@utwente.nl> writes:

>  element A (abstract=true)
>  element B (substitutionGroup="A")
>  element C (substitutionGroup="A")
>  element D () - sequence - element (ref="A")
>
> Now I convert Schema 1 to a "validation equal" Schema 2, presented
> below:
>
>  element B ()
>  element C ()
>  element D () - sequence - choice -- element (ref="B")
>                                   \_ element (ref="C")

is correct, and can always be done for any schema (not _not_ schema
document).

The subsequent messages in this thread don't contradict the above
statement, as long as the fact that in the mixed-namespace example
offered the schema involved does indeed require both schema
_documents_ to be processed, so the correct 'choice' becomes:

> Both (ns2:F and ns1:D) - sequence - choice - ref="ns1:B" 
>                                            - ref="ns1:C" 
>                                            - ref="ns2:E" 
 
As you correctly state, no wildcard required.

ht
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  Henry S. Thompson, HCRC Language Technology Group, University of Edinburgh
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Received on Tuesday, 6 January 2004 09:33:22 UTC