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Re: Rework on SOAP 1.2 Part 2: Section 2 and 3

From: Jean-Jacques Moreau <moreau@crf.canon.fr>
Date: Mon, 18 Mar 2002 11:30:49 +0100
Message-ID: <3C95C1D9.8C0FA3E7@crf.canon.fr>
To: Martin Gudgin <marting@develop.com>
CC: "Williams Stuart" <skw@hplb.hpl.hp.com>, Noah Mendelsohn <noah_mendelsohn@us.ibm.com>, XML Protocol Discussion <xml-dist-app@w3.org> 
So you are essentially collapsing/folding the terminal nodes into their edges?
Wouldn't the alternate graph below be more symmetric?

Jean-Jacques.

Martin Gudgin wrote:

> <structA>
>   <edgeB>terminalB</edgeB>
>   <edgeC>terminalC</edgeC>
>   <edgeD>
>     <structE>
>       <edgeF>terminalF</edgeF>
>       <edgeG>terminalG</edgeG>
>     </structE>
>   </edgeD>
> </structA>

<structA>
  <edgeB><term>terminalB</term></edgeB>
  <edgeC><term>terminalC</term></edgeC>
  <edgeD>
    <structE>
      <edgeF><term>terminalF</term></edgeF>
      <edgeG><term>terminalG</term></edgeG>
    </structE>
  </edgeD>
</structA>
Received on Monday, 18 March 2002 05:32:30 GMT

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