W3C home > Mailing lists > Public > www-style@w3.org > August 2011

Re: magic corner gradient revisited

From: Tab Atkins Jr. <jackalmage@gmail.com>
Date: Mon, 8 Aug 2011 18:54:15 -0700
Message-ID: <CAAWBYDDE8mo097A0Z+W82_i=E68xmwGFwTeB1wMBreVQH5HhBg@mail.gmail.com>
To: Brian Manthos <brianman@microsoft.com>
Cc: Brad Kemper <brad.kemper@gmail.com>, fantasai <fantasai.lists@inkedblade.net>, www-style list <www-style@w3.org>
On Mon, Aug 8, 2011 at 6:41 PM, Brian Manthos <brianman@microsoft.com> wrote:
> # If the argument specifies a corner to angle towards, the gradient must be rendered identically to an angle-based gradient with an angle chosen such that the endpoint of the gradient is in the same quadrant as the indicated corner, and a line drawn perpendicular to the gradient-line through the center of the box intersects the two neighboring corners.
>
> This phrasing doesn't narrow down the angle that must be used.  In fact, pretty much any angle in the quadrant satisfies the specified criteria.

No, there is a unique line that both passes through the center of the
box and intersects the appropriate corners.  (It's just the line
between the two corners.)  There is thus a unique gradient angle that
places the endpoint in the right quadrant and produces a gradient line
perpendicular to the aforementioned line.

~TJ
Received on Tuesday, 9 August 2011 01:55:10 GMT

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