Re: [whatwg/url] Disallow invalid IPv4 in IPv6 parser (#196)

This does not appear to give the correct results.

Given input `::1.`, there should be a failure, but following the new algorithm, there is none:

step 5: pointer = 2, piece pointer = compress pointer = 1

step 6 (main):
 - step 4: value = 1, pointer = 3, length = 1
 - step 6: c = "." => pointer = 2, ipv4 = true

step 10:
 - first round, c = "1"
   - step 3: value = 1, pointer = 3
   - step 4: no failure (c is "." now because pointer incremented in step 3)
   - new step "if dots seen is 3 and c is not the EOF code point, failure": no failure (c is ".", not EOF)
   - new step "if c is "." increase pointer and dots seen by one": pointer is now 4, so c = EOF, so loop exits

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