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[Bug 20149] New: [Shadow]: Specify the order of stylesheets in different tree scopes for apply-author-styles.

From: <bugzilla@jessica.w3.org>
Date: Thu, 29 Nov 2012 05:09:29 +0000
To: public-webapps-bugzilla@w3.org
Message-ID: <bug-20149-2532@http.www.w3.org/Bugs/Public/>

            Bug ID: 20149
           Summary: [Shadow]: Specify the order of stylesheets in
                    different tree scopes for apply-author-styles.
    Classification: Unclassified
           Product: WebAppsWG
           Version: unspecified
          Hardware: PC
                OS: All
            Status: NEW
          Severity: normal
          Priority: P2
         Component: Component Model
          Assignee: dglazkov@chromium.org
          Reporter: tasak@google.com
        QA Contact: public-webapps-bugzilla@w3.org
            Blocks: 14978

If some shadow root's apply-author-styles is true, styles in a different tree
scope, e.g. document, will be applied to elements in the shadow dom tree.

In this case, we need to compare document positions of styles in a document
tree and styles in the shadow dom tree. (also need to consider styles in an
enclosing shadow tree).

I'm not sure whether it is ok to use a document position of a shadow host to
solve the above case or not.
If ok, I'm thinking of the following algorithm:

Suppose that two nodes, A and B. A is in some shadow dom tree and B is in
another shadow dom tree. B's tree scope is an ancestor tree scope of A's.

To compare document position of A and B:
(1) going up from node A to the shadow host C in B's tree scope. I mean, A's
host -> A's host's host... to reach B's tree scope.
(2) compare C with B (by using Node::compareDocumentPosition).

In general, 
(1) finding a common ancestor node of A and B. 

(2) comparing immediate children of the common ancestor, A' and B'. A' is an
ancestor node of A and B' is an ancestor node of B.

(3) if A' and B' are in the same tree scope, just compare A' with B' in the
original compareDocumentPosition's way.

(4) if A' is a shadow root and B' is not a shadow root, treat A' as a shadow
host. Since B' is a child of the shadow host, B' is following A'. So B is
following A.

(5) if both A' and B' are shadow roots, see which is a younger shadow root and
follow the rule defined in shadow dom spec: 
"When a shadow host has multiple shadow roots, the sorting order of CSS rules,
defined in shadow roow style sheets, in ascending order of precedence must
match the order of the tree stack, ending with the youngest tree."

Best regards,
Takashi Sakamoto

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Received on Thursday, 29 November 2012 05:09:30 UTC

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