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Re: clip-path contradiction

From: Cameron McCormack <cam@mcc.id.au>
Date: Thu, 18 Nov 2010 11:22:01 +1300
To: Erik Dahlstrom <ed@opera.com>
Cc: "public-svg-wg@w3.org" <public-svg-wg@w3.org>
Message-ID: <20101117222201.GD6812@wok.mcc.id.au>
Erik Dahlstrom:
> in the definition of the 'clipPath' element[1] it's stated that you
> can apply the 'clip-path' property to a 'clipPath' element and that
> the result is the intersection of the two clip paths. However, in
> the 'clip-path' property definition the 'clipPath' element isn't
> listed as one of the elements to which 'clip-path' applies to. I
> think it should be added there.

Yes, I think so.  Note that in SVG 1.1 First Edition clipPath was
defined to be a container element.  I think that it was removed from
that list because that implied certain other requirements on clipPath
that didn’t make sense (though I don’t remember what these were now).

-- 
Cameron McCormack ≝ http://mcc.id.au/
Received on Wednesday, 17 November 2010 22:22:37 GMT

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