From: Stephen Buxton <Stephen.Buxton@oracle.com>

Date: 16 Feb 04 14:40:38

Message-Id: <200402162240.i1GMecG21514@rgmgw5.us.oracle.com>

To: public-qt-comments@w3.org

Cc:

Date: 16 Feb 04 14:40:38

Message-Id: <200402162240.i1GMecG21514@rgmgw5.us.oracle.com>

To: public-qt-comments@w3.org

Cc:

SECTION 6.2.5: op:numeric-integer-divide The statement "...ignoring any remainder..." is not helpful in the case that either the numerator or the divisor or both is negative, since there is no universally accepted definition of how to perform such integer divisions. In SQL, the decision was to follow Fortran's MOD and C's fmod functions to define the remainder (see ANSI INCITS H2 paper H2-2003-390, available on request from Fred Zemke, Oracle). These precedents both define that the sign of the remainder is the same as the sign of the numerator. Thus numerator = divisor * quotient + remainder where sign(remainder) = sign(numerator) and abs(remainder) < abs(numerator) completely specifies the integer quotient and remainder. This happens to agree with all four of your examples, so it is presumably what you meant. This is corroborated by the discussion in 6.2.6 op:numeric-mod. - Steve B.Received on Monday, 16 February 2004 17:40:40 UTC

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