override
problemsOur goal is to construct a tree of include and overide connections with no duplicate leaves. However we will speak as if we're dealing with a graph, because the fact that we're building a tree is something that eventually will need to be proved, not just assumed/asserted. The nodes of the graph (which we'll call G) are schema documents, identified by their base URIs, which we take to be the URIs of the schema documents as retrieved after all redirection has occurred.
Notation:
.sd
is the
schema document of node n, n.uri
is its
base URI and n.markers
is its set of markers (see
below). Node(u)
is a new node of G
composed of a newly-retrieved schema document whose base URI is u
and an empty marker set.e, f, ... will be variables over edges.
Edge(n,m,l)
is a new edge
of G from
node n to node m with label l. e.from
, e.to
and e.label
access the
start node, end node and label of an edge, respectively. n.out
and
n.in
are the sets of edges from/to node n, respectively.
include
onlyThis algorithm reconstructs XSV's handling of
re-entrant and circular includes
.
= Node(root)
to G = {r}
and a set of
nodes already processed P = {}
.uri
=
n.uri
and m.markers
=
n.markers
, then
.to =
n, remove e from Ginclude
EII or import
EII with a
schemaLocation
attribute (call that EII i) in n.sd.[children]
=
Node(
i/@schemaLocation)
to Ginclude
, add all the members of n.markers
to m.markers
include
and its inclusion of m.sd
is
a chameleon inclusion, then add
tns(
n.sd)
to m.markers
Edge(
n,
m,"include" or
"import" as appropriate)
to GThere is slightly more mechanism here than is needed (edge labels are not used, 6.b.ii and 6.b.iii are mutually exclusive and the marker set of a node is always either empty or consists of a single URI). This is to prepare the way for handling override as well.
On the other hand, the treatment of import
is
oversimplified, and redefine
is not mentioned at all.
I think it's reasonably obvious that the result of the above is a tree rooted at r and that the leaves are unique. Representation checking and schema construction can then proceed bottom-up with respect to that tree. That doesn't mean that a given schema document will only be processed once: if is chameleon-included with multiple including namespaces, or is both chameleon and non-chameleon included, it will occur at multiple leaves (with different values for its markers) and be processed multiple times, but necessarily so, and with different results in each case.
(In XSV (vintage Schema 1.0), the actual algorithm dispenses with
Q, and simply recurses at 6.b.iv. This means that once it gets to
the end of the include [children]
in step 6, it can check and process
the rest of the [children]
and add the corresponding components
to the schema component for the appropriate namespace, and no spurious
duplicates will ever by encountered.)
override
onlyIgnoring include
for the time being (and import
and redefine
).
= Node(root)
to G = {r}
, a set of
nodes already processed P = {}
.uri
=
n.uri
and there exist nn,
tt, ii, jj, uu and vv such that
<
nn,
tt,
uu,
ii>
ε
n.markers
and
<
nn,
tt,
vv,
jj>
ε
m.markers
and it's not the case that
both uu =
vv and ii =
jj, then
there are conflicting overrides with respect to the component named nn of type
tt, signal the relevant error and abandon override
processing.uri
=
n.uri
and n.markers
⊆
m.markers
, then
.to =
n, remove e from G.uri
=
n.uri
and m.markers
⊂
n.markers
remove the subtree rooted at
m from G, P and/or Q,
that is
ε
m.in
, remove e from G ε
m.out
, remove e from G and remove
e.to
from G and P or
Q as well, and all the edges in e.to.out
,
and so on, but not removing n, if
encountered at any point in this recursionoverride
EII (call it o) in n.sd.[children]
=
Node(
o/@schemaLocation)
to G.markers
to m.markers
.[children]
(call it
d), if n.markers
does not contain a
tuple of the form
<
d/@name,local-name(
d),...>
,
then add a tuple of the form <
d/@name,local-name(
d),
n.uri,
o/position()>
to m.markers
Edge(
n,
m,"override")
to GIf the node removed from Q at step 4 is always among those with the largest marker set, I believe wasted traversals (those removed at 7.a) will be kept to a minimum.
If this algorithm completes without error, once again we have a tree
with uniquely labelled leaves. To avoid duplication of effort when there are
multiple compatible overrides of the same schema document (that
is, leaf nodes with the same uri
but markers
neither
of which is a subset of the other), I think
the following suffices:
uri
s), take the union of all their markers
and
transform the schema document once, using the definitions and declarations
identified by markers in that union to override local ones, to produce a new
schema documentoverride
elements, these are not
processed, since their targets must have been pruned at some point in Oinclude
the result in each node in the tree which has
an edge ending at one of the leaf nodes and erase that edgeAs specified this algorithm doesn't handle include
, but
modifying it to treat <include schemaLoc="..."/>
as if it were
<override schemaLoc="..."/>
should be straightforward.
Consider the simple example offered by Mike Kay. The tree resulting from the application of Algorithm O is as follows:
["P.xsd",{}]
|
["Q.xsd",{<'doc','element',"P.xsd",1>}]
|
["P.xsd",{<'doc','element',"P.xsd",1>}]
And the associated documents will (schematically) look like this:
{doc as xs:date}
|
{doc as xs:date}
|
{}
Which I take it is the result Mike Kay wanted.
What happens if we start at Q?
["Q.xsd",{}]
|
["P.xsd",{}]
|
["Q.xsd",{<'doc','element',"P.xsd",1>}]
|
["P.xsd",{<'doc','element',"P.xsd",1>}]
This may look as if it's the same as the previous case, but the algorithm doesn't think so:
{doc as anon, doc as xs:date}
|
{doc as xs:date}
|
{doc as xs:date}
|
{}
Which is not a conformant schema!
Mike, is that what you expected? Is it what the current resolution calls for? Is it right?