Re: Question on XSD elements in groups

Arshad Noor wrote:

  Hi,

> Since I can only have a Symkey, SymkeyError or a combination
> of both in the to-be-defined element, why does NB think there
> will be ambiguity?

  Because when it will encounter a Symkey, it will be not possible to
know in the choice if this is the Symkey from the Symkey alternative,
or from the group alternative.

> How do I go about accomplishing what I want?

  The idiomatic solution is to use a choice on Symkey and optional
SymkeyError, or just a SymkeyError:

    <xs:choice>
       <xs:sequence>
          <xs:element ref="Symkey"/>
          <xs:element ref="SymkeyError" minOccurs="0"/>
       </xs:sequence>
       <xs:sequence>
          <xs:element ref="SymkeyError"/>
       </xs:sequence>
    </xs:choice>

  For more information, look for "UPA" or "UPA violation".

  Regards,

--drkm
























      _____________________________________________________________________________ 
Envoyez avec Yahoo! Mail. Une boite mail plus intelligente http://mail.yahoo.fr

Received on Monday, 23 June 2008 09:31:04 UTC