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Re: Proposal for dealing with root

From: <noah_mendelsohn@us.ibm.com>
Date: Wed, 24 Apr 2002 23:06:43 -0400
To: <xml-dist-app@w3.org>, <martin.gudgin@btconnect.com>, <jacek@systinet.com>
Message-ID: <OF20200D3C.F5C1BEF6-ON85256BA6.00041EAC@lotus.com>
I guess I'm not quite sure why it matters where serialization starts, but
since those of you who implement the system seem to need to want to know,
I won't slow down the discussion further.   I had presumed that, in the
latest design, serialization covered all elements within the scope of
suitable "encodingStyle" elements, with no notion of where the
serialiation starts.  Bottom line:  I'm still not sure why we would need
such a concept, but don't waste time trying to convince me.  Thanks.

------------------------------------------------------------------
Noah Mendelsohn                              Voice: 1-617-693-4036
IBM Corporation                                Fax: 1-617-693-8676
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"Martin Gudgin" <martin.gudgin@btconnect.com>
Sent by: xml-dist-app-request@w3.org
04/24/02 11:10 AM


        To:     "Jacek Kopecky" <jacek@systinet.com>,
<noah_mendelsohn@us.ibm.com>
        cc:     <xml-dist-app@w3.org>
        Subject:        Re: Proposal for dealing with root


----- Original Message -----
From: <noah_mendelsohn@us.ibm.com>
To: "Jacek Kopecky" <jacek@systinet.com>
Cc: <martin.gudgin@btconnect.com>; <xml-dist-app@w3.org>
Sent: Wednesday, April 24, 2002 2:35 PM
Subject: Re: Proposal for dealing with root


> I'm asking what "serialization root" means.  The encoding exists only to
> move the graph from one place to another.  What does it mean to have a
> root concept in the encoding that's not in the graph?

Well, one could argue that even with a graph that has no root,
serialization
has to start somewhere...

Gudge
Received on Thursday, 25 April 2002 09:40:05 GMT

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