W3C home > Mailing lists > Public > www-xsl-fo@w3.org > August 2002

Re: Using substring and gaining a <a href="...">...<a>

From: G. Ken Holman <gkholman@CraneSoftwrights.com>
Date: Thu, 15 Aug 2002 19:14:13 -0400
Message-Id: <>
To: www-xsl-fo@w3.org

At 2002-08-14 08:30 -0400, Wolfgang.Schreurs@ingbank.com wrote:
>The input would be:
><spotlight_text ID="texthref">bla bla <a
>href="http://www.apple.com">apple</a> bla </spotlight_text>
>This is the XML file...
>The desired output from the XSL file would be:
>bla bla apple <http://www.apple.com> bla
>where there is a limit of 60 chars, but we allready have the limit by using
>this code in the XSL file:
>(I think I can keep this the way it is.)

No, I'm sorry I wasn't clear before but you cannot use any function on the 
length of the markup.  XSLT is for manipulating nodes, not manipulating markup.

><xsl:template name="substring_template">
><xsl:variable name="right_text_string" select="spotlight_text"/>
><xsl:value-of select="substring($right_text_string,0, 60)"/>
>How would I get the desired output? Currently it shows the line of text, but
>the hyperlink isn't used, it looks like substring() removes the '<a
>href="...">...</a>' tags, but keeps the input between the tags. ie, I get
>this output:
>bla bla apple bla

Yes, because substring() infers string() on the first argument which looks 
at the text nodes and gives you only the concatenation of the text nodes 
without any markup.

If you are processing <spotlight_text>, then do the following:

   <xsl:template match="spotlight_text>
     <xsl:copy-of select="node()"/>

The above will copy all nodes from your input tree to your result tree and 
when those result tree nodes are serialized as syntax you will get the 
hyperlink restored.

You will *not* be able to measure the length of the markup, so you will not 
be able to reliably restrict the output to only 60 characters total.  You 
will have to use a different technology to get that kind of control over 
the generated markup.

>I hope this is better to understand.

I hope it has been successfully conveyed that you are asking about working 
with markup, yet XSLT only works with abstract nodes of a node tree.

>I don't use the Formatting Object

Then I suggest you ask future questions to:


I hope this helps.

................. Ken

Upcoming hands-on in-depth 3-days XSLT/XPath and/or 2-days XSL-FO:
-                               North America:  Sep 30-Oct  4,2002
-                               Japan:          Oct  7-Oct 11,2002

G. Ken Holman                 mailto:gkholman@CraneSoftwrights.com
Crane Softwrights Ltd.          http://www.CraneSoftwrights.com/f/
Box 266, Kars, Ontario CANADA K0A-2E0  +1(613)489-0999 (Fax:-0995)
ISBN 0-13-065196-6                       Definitive XSLT and XPath
ISBN 1-894049-08-X   Practical Transformation Using XSLT and XPath
ISBN 1-894049-07-1                Practical Formatting Using XSLFO
XSL/XML/DSSSL/SGML/OmniMark services, books (electronic, printed),
articles, training (instructor-live,Internet-live,web/CD,licensed)
Next public training:              2002-08-26,27,09-30,10-03,07,10
Received on Thursday, 15 August 2002 19:17:37 UTC

This archive was generated by hypermail 2.3.1 : Tuesday, 6 January 2015 20:58:26 UTC