Re: XPath Equality-expr

Right. Thanks.

Kay Michael wrote:
> 
> XPath section 3.4, fifth para first sentence.
> 
> I believe this should read: When neither operand is a nodeset, then the
> operands of an EqualityExpr *that is not a RelationalExpr* are converted to
> a common type...
> 
> (because, rather confusingly, every RelationalExpr is an EqualityExpr).
> 
> It might be better to use some other form of words to distinguish this
> paragraph from the following one, e.g. doing it in terms of the operator
> rather than the syntactic construct.
> 
> Mike Kay