TEST: 5 of 7: was Re: Revisiting AllDisjoint

Ian, Jim, Jonathan

I have include Ian's test from

http://lists.w3.org/Archives/Public/www-webont-wg/2003Jul/0157

as

http://www.w3.org/2002/03owlt/editors-draft/draft/proposedByIssue#I5.21-002

I could do with a few more reptile names. I currently have 6 (taken from Jim's 
message)

The number of triples in Ian's idiom is 6 + 5N = 36

The number of triples in the O(N^2) version is N(N+1)/2 = 21

If we had N=11 (another five reptiles) we would have 61 verses 66 triples, 
showing that Ian's idiom is better (with N>=11).


Jeremy

Received on Wednesday, 23 July 2003 13:20:26 UTC